Question

Develop a PLC ladder logic for motor lockout to prevent a machine operator from starting a motor that has tripped off more than 5 times in an hour. The sequence of operation is given below. Please use the same names (or addresses) for input/outputs as given below. Assume the PLC tick time is 10ms 18j List of Inputs and Outputs: Sequence of Operations: Inputs: 00: Start (Momentary push button) The normally open overload (OL)-retay 01 : Stop (Momentary push button) 02: Overload relay (Normally Open) 2) Every time the motor stop due to an overload 03: Reset Push button Outputs: 03: Motor 04 Lock-out Light Timers & Counters: 05: Timer (TI) 06: Timer (T2) 07: Counter(CI) Internal Relays: contact momentarily closes each time an condition, the motor start circuit is locked out for 5 min. 3) If the motor trips off more than 5 times in an hour, the motor start circuit is permanently locked out and cannot be started until the reset button is actuated. 4)The lock-out pilot light is switched on whenever a permanent lock-out condition exists. Address 10 to 20

Answer 1

Reset Push Button 1:0 Reset all program B30 progran B3:0 0006 Bul. 1762 C5:0 RES Timer for 4 hour T4:0 CRES Timer for 4 hour RES 0007 END
0000 rung- start stop logic for program

0001 rung- motor start and stop condition

0002 rung, 0003 rung and 0004 rung are used for creating timer and counter sequence

0005 rung- used for turning ON lock out light when 5 times overload signal comes

0006 rung used to reset all condition by reset push button