Question

III. For each given transfer function below 1) Find damping factor ς, natural frequency w , Settling Time Ts, Rise time Tr and Percent Overshoot P.O Confirm results with Matlab 240 3s2+12s 240 GOD 4s2 +24s 600) 125 a)T)+24s+600) e) T3)+0.0s + 125) T2(s)= b)

Answer 1

s o (2%) (4 Rise Jime 7-0 0.224. = 2 sec g) Rise divne j : 7-а 314-1:344 -(01224-) 2, D. 4883 OY 48.83%

Coo s. J)

MATLAB Command Window >>tl-tf ([600],[4 24 600]) stepinfo (tl) damp (t1) t2-tt( [240], [3 12 240)) stepinfo (t2) damp (t2) t3-tf ([125], 1 0 125]) stepinfo (t3) damp (t 3) t1 = 600 4 S2 + 24 s 600 Continuous-time transfer function. RiseTime: 0.1031 SettlingTime: 1.1550 SettlingMin: 0.7964 SettlingMax: 1.4517 Overshoot: 45.1719 Undershoot 0 Peak 1.4517 PeakTime: 0.2610 Eigenvalue Damping ecuency 2.45c-01 2.45e-01 -3.00e+00 1.19e+011 3.00e+00-1.19e+011 1.22e+01 1.22e+01 (Frequencies expressed in rad/seconds) 240 3 s2 +12 s 240 Continuous-time transfer function ans

MATLAB Command Window RiseTime: 0.1383 SettlinqTime: 1.8902 SettlingMin: 0.7639 SettlingMax: 1.4852 Overshoot: 48.5150 Undershoot: 0 Peak: 1.4852 PeakTime: 0.3684 Eigenvalue Frequency Damping -2.00e+00+8.72e +001 -2.00e+00- 8.72e +001 2.24e-01 2.24e-01 8.94e+00 8.94e+00 (Frequencies expressed in rad/seconds) t3 s2 125 Continuous-time transfer function RiseTime: NaN SettlingTime: NaN SettlingMin: NaN SettlingMax: NaN Overshoot: NaN Undershoot NaN Peak: Inf PeakTime: Inf Eigenvalue Damping Frequency 0.00e+00+1.12e+011 0.00e+00 - 1.12e+011 0.00e+00 0.0De+00 1.12e+01 1.12e+01 (Frequencies expressed in rad/seconds)
All calculations done by hand are on approximate basis done with the calculator.

Please upvote our work. THANK YOU!!