Question

Exercise3 Suppose you have several points with coordinates (xk, v) located in the 2-D plane. The points are sorted from smallest to largest x coordinate. You want to find the slope of the line between each successive pair of points, i.e., between (xbw) and (xkl.yk. These are the points: (-5, 9), (-1, 5), (2,7), (8, 12), (13, 5), (15, -4), (20, 0), (45, 3), (66, 10), (70, 8) Write a program that meets these requirements: Create a 1-D array named x and initialize it with these values -5, 1, 2, 8, 13, 15, 2«, 45, 66, 7e Create a 1-D array named y and initialize it with these values: 9, 5, 7, 12, 5, -4, 0, 3, 10, 8 Use either a for or while loop and array indexing to calculate the slope between successive pairs of points. Store each slope value in another 1-D array named slope. . Example: slope[o] ([1yO])/(x1-xO]) (5-9)/(-1-(-5)-1 AFTER all of the slopes have been calculated, use a separate loop to print out the values that are stored in the slope array. Show the results to at most three (3) decimal place. Need to use while and break statements Copy and paste your finished slope calculation program here:

Answer 1

#include <iostream>

int main()
{
int x[]={-5,-1,2,8,13,15,20,45,66,70};// initializing x array
int y[]={9,5,7,12,5,-4,0,3,10,8}; // initializing y array
float slope[9]; //initializing slope array
for(int i=0;i<9;++i)
{
slope[i]=(float)(y[i+1]-y[i])/(x[i+1]-x[i]); // calculating slope
}
  
for(int i=0;i<9;++i)
{
printf(" %0.3f ",slope[i]); // printing slope upto 3 decimal places
}
return 0;
}