Typed Please, Thank you 2. Instead of offering no premium free channels as in Prob- pective 0 lem 1, suppose that two free premium channels are in- cluded in the 3-For-All service offer. Given past r...
2. Instead of offering no premium free channels as in Prob- pective 0 lem 1, suppose that two free premium channels are in- cluded in the 3-For-All service offer. Given past results what is the probability that a. fewer than 3 customers will subscribe to the 3-For-All iu or th to the 3 service offer? b. 0 customers or 1 customer wl subscribe to the 3-For cus All service offer? c. more than 4 customers w subscribe to the 3-For-All service offer? d. Compare the results of (a) through (c) to those of 1 e. Suppose that in the actual survey of 50 prospective cu customers, 6 customers subscribe to the 3-For-All ser- ld cust mers vice offer. What does this tell you about the previous estimate of the proportion of customers who would Premium ChannelsSubscriptionsf What do the results in (e) tell you about the effect of Number of Free Probability of subscribe to the 3-For-All service offer? offering free premium channels on the likelihood of 0 0.02 0.04 0.06 0.07 0.08 0.085 obtaining subscriptions to the 3-For-All service? 2 3 4
2. Instead of offering no premium free channels as in Prob- pective 0 lem 1, suppose that two free premium channels are in- cluded in the 3-For-All service offer. Given past results what is the probability that a. fewer than 3 customers will subscribe to the 3-For-All iu or th to the 3 service offer? b. 0 customers or 1 customer wl subscribe to the 3-For cus All service offer? c. more than 4 customers w subscribe to the 3-For-All service offer? d. Compare the results of (a) through (c) to those of 1 e. Suppose that in the actual survey of 50 prospective cu customers, 6 customers subscribe to the 3-For-All ser- ld cust mers vice offer. What does this tell you about the previous estimate of the proportion of customers who would Premium ChannelsSubscriptionsf What do the results in (e) tell you about the effect of Number of Free Probability of subscribe to the 3-For-All service offer? offering free premium channels on the likelihood of 0 0.02 0.04 0.06 0.07 0.08 0.085 obtaining subscriptions to the 3-For-All service? 2 3 4