Question

A cell phone emits a 1.9 GHz electromagnetic wave. Ata location near the phone, the intensity of the wave is measured to be 0
0 0
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Answer #1

18.

Intensity = I = 0.067 W/m2

\varepsilon _{0} E^{2}/2 = I/C

Therefore

2 21

Where \varepsilon _{0 = 8.85 x 10-12, C =speed of light = 3x108

putting values we get

E2 = 50.47

therefore , E- V50.47 = 7.1 N/C

option (E) is correct here.

19.

B = \frac{E}{C} =7.1 = 2.37X10-8 3X108

option (A) is correct

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A cell phone emits a 1.9 GHz electromagnetic wave. Ata location near the phone, the intensity of the wave is measured to be 0.067 W/m2 10 pt What is the amplitude of the electric field at this lo...
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