Solution:-
3)
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: The sample data fits the distribution of unloaded dice.
p1 = p2 = p3 = p4 = p5 = p6
Alternative hypothesis: At least one of the proportions in the null hypothesis is false.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square goodness of fit test of the null hypothesis.
Analyze sample data. Applying the chi-square goodness of fit test to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic. Based on the chi-square statistic and the degrees of freedom, we determine the P-value.
DF = k - 1 = 6 - 1
D.F = 5
(Ei) = n * pi
X2 = 13.44
X2Critical = 15.09
Rejection region is X2 > 15.09
where DF is the degrees of freedom, k is the number of levels of the categorical variable, n is the number of observations in the sample, Ei is the expected frequency count for level i, Oi is the observed frequency count for level i, and X2 is the chi-square test statistic.
Interpret results. Since the X2-value (13.44) does not lies in the rejection region, hence we failed to reject the null hypothesis.
From the above test we cannot conclude that the die is loaded.
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