Question

Part D What is the angular radius 0 of the first dark ring for a point source being imaged by this telescope? Use 550 nanometers for the wavelength,since this s near the average for visible light Express your answer in degrees, to three significant figures 197 ΑΣφ Request Answer Diftraction due to a circular aperture is important in astronomy Since a tolescopo has a circular aporture of finite size, stars are not imagod as points, but rathor as iftraction patterns. Two distinct points are said to be just rosolved o o have the smallest soparation for which you can confidonily tell that there are two ponts instoad of just ono) when the conter of one point's dittraction paltom is found in the first dark ning of the other point's diffraction paltom. This is called Rayloigh's criterion for Consider a tolescope with an aperture of diamoter 0 900 m Part D What is the angular radus O of the tust dark ring for a pont source bing nogod by thes toloscope? Use 550 nanometers for the average for visible light wavelongth, since thirs is near the Express your answer in degrees, to three significant figures 0

Answer 1

Part D )

$\lambda$ = 550 nm

D = 0.96 m

$\theta$₁ = ?

using equation sin$\theta$₁ = 1.22 $\lambda$ / D

= 1.22 x 550 x 10^-9 / 0.96

= 6.9895 x 10^-7

= sin^-1 6.9895 x 10^-7

$\theta$₁ = 4.004688 x 10^-5 degrees