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1. (a) A solid cylindrical straight wire of vadius a has a current I. flowng down t Eftha cument untfermly distributed over t
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Answer #1
  1. . radius of the wire = a

consider a lengh of 1 mt of the wire

surface area A = 2media%2Fc4c%2Fc4ccebad-f028-4c11-b8ea-22a sq.m

current flowing through the wire = I

entire current flows through the surface

current density = I/2media%2F243%2F243c0f2e-6d55-44e4-b150-5ca A/sq.m

  1. consider a cylindrical shell fo radius r and thickness dr and of length 1 m

volume of the shell dV = 2media%2Fc6f%2Fc6fba8fd-a537-4996-bffe-8frdr

Let J = kr2 , given J grows quadratically with r

current through the shell

dI = JdV = 2media%2F812%2F8121f9d3-a7f3-4af3-afa6-24kr3dr

Total current through the wire

       media%2F56e%2F56ee8d1c-31e4-44c4-a488-15

             = media%2Fa50%2Fa50180f9-8496-467a-ba71-12ka4/2

k = 2I/media%2F252%2F252eef38-e15e-423b-bd3e-3fa4

current density J(r) = kr2 = 2Ir2/media%2Fe48%2Fe48b0081-5c09-4e43-a56e-0da4

  1. . Surface current density is the current flowing through a unit width perpendicular to the flow of current

consider a strip of width dr and radius r

length of the strip moving per unit time = media%2F85c%2F85c6fc59-f3b4-442f-9623-f6r

charge on the strip dq= media%2Fadf%2Fadff1b94-71cd-40f9-8e1a-4ardr

current I = dq/dt = media%2F98f%2F98ffc70b-49ea-41c9-8444-6ardrmedia%2F77f%2F77f5e80a-d2b7-405d-a95b-b9

surface current density K = media%2F42e%2F42e71e3a-f467-4a8a-a4d6-06rdrmedia%2F968%2F96863e71-ceb6-430e-8ecd-d2/dr = media%2Fac0%2Fac018604-1606-4fa6-9250-e2rmedia%2Fe1a%2Fe1a755bf-8a0e-4a7b-b62a-e3

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1. (a) A solid cylindrical straight wire of vadius a has a current I. flowng down t Eftha cument untfermly distributed over the outer surface of the wire (mone ts flowm throug)h the volume of the...
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