Question

Identify the critical​ value(s). Select the correct choice below and fill in any answer boxes within your choice.

The weights (in pounds) of 6 vehicles and the variability of their braking distances (in feet) when stopping on a dry surface are shown in the table. Can you conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry surface? Use α= 0.01 Weight, x Variability in braking distance, y 囲Click here to view a table of critical values for Student's t-distribution. 59505380 6500 5100 5850 4800 ce, y | 1 74 1.991 187 L 162 1165 1.74 1.99 1.871.62 1.651.50

​(Round to three decimal places as​ needed.)

*The critical value is

*The critical values are

B. Calculate the test statistic

t= (Round to three decimal places as​ needed.)

c.

What is your​ conclusion?

There▼ enough evidence at the 5​%level of significance to conclude that there▼is a significant linear correlation between vehicle weight and variability in braking distance on a dry surface.

Answer 1

(x-x)(y-y 4.1222 56.6944 127.9722 53.8056 -19.8444 181.9056 291.2667 (y-y) 0.0001 0.0685 0.0201 0.0117 0.0061 0.0521 0.1587 (x-x) S.No 1 2 1.74 1.99 1.87 1.62 1.65 1.5 10.37 1.7283 5950 5380 6500 5100 5850 4800 33580 5596.6667 124844.4444 46944.4444 816011.1111 246677.7778 64177.7778 634677.7778 1933333.3333 SSX 4 Total SSY Mean null hypothesis Alternate Hypothesis 0 0 for 0.05 level,two tailed test and n-2 4 degree of freedom, critical t- Decision rule: 2.7764 reject Ho if absolute value of test statistic |t| >2.776 correlation coefficient r- 0.526 test statistic: 1.2365 P value 0.2839

The critical values are -2.776 , 2.776

b)

test statistic t =1.236 (try 1.237 if this comes wrong)

c)

There is not enough evidence at the 5​%level of significance to conclude that there is a significant linear correlation between vehicle weight and variability in braking distance on a dry surface.