Question

Please explain the solution done below to the smallest detail.

Data: [kg] macar := 10 = 500 TTL な:0.01 [m] 9: 9.81 p30 deg 0.524 TTL 1.-_.mte .r2 = 5. 10-5 Position 1 potential energy kinetic energy Position 2 E,1-0 agring0.5.k.s" potential energy kinetic energy x2 T. Equation solve,,ftoat,3 [-0.739 2.0.739 mar t1 1.772 u:= 0.739 Non-Commercial Use Only

Answer 1

Given, Mass Of each oheel 1kg Radius of ioheel Yo oolm p Agle of inclination-3o lengtn of inclined plare 5 om height of indlined plare s sinp-h 9. Pod tior③ By the pincipe of corervotion of Einesg Tnitially Springexporsion

KEnitial velocity-o echeral pe, +KE1.PF.HEf호 + K5 叉 636汗V4V2+1 500×012 This is the compleze explorotion, To be soxt, Acconding to puirciple of conewation of fnexg b opplicd and the requinea vake is found If these is spsing add spring enesgy Ch) If these otating body add 40d-et-e