LT An aluminum rod of diameter D 2.5 cm and of length from a wall maintained at T, 300"C. The.coovective heat coefficient h 17 W/m2-K with an ambie.t air temperature T Thermal conductivity k =...
LT An aluminum rod of diameter D 2.5 cm and of length from a wall maintained at T, 300"C. The.coovective heat coefficient h 17 W/m2-K with an ambie.t air temperature T Thermal conductivity k = 204 WmK. Assume there is e luid by convection from the end of the rod, which is at temperature Ta. Using 2. -38c. nergy transfer to the a finite difference method, with Ax = 5 cm, the fo be derived for the solution of the problem: llowing nodal equations may 2.033T2 T3 301.265 -12 + 2.03313-Ta = 1.265 T3 1.021T4-0.7918 Solve the above system of equations for the unknown temperatures Tz. Ta and T4 by using the Gauss-Jordan elimination method 2.033 0 2 [301.265 033 -1 T3 1.265 -1.021IT, -0.7918 10.4919 0 0 I[T2l [148.1871 0.6489396.978 -1.021 IT,J L-0.7918 LO
LT An aluminum rod of diameter D 2.5 cm and of length from a wall maintained at T, 300"C. The.coovective heat coefficient h 17 W/m2-K with an ambie.t air temperature T Thermal conductivity k = 204 WmK. Assume there is e luid by convection from the end of the rod, which is at temperature Ta. Using 2. -38c. nergy transfer to the a finite difference method, with Ax = 5 cm, the fo be derived for the solution of the problem: llowing nodal equations may 2.033T2 T3 301.265 -12 + 2.03313-Ta = 1.265 T3 1.021T4-0.7918 Solve the above system of equations for the unknown temperatures Tz. Ta and T4 by using the Gauss-Jordan elimination method 2.033 0 2 [301.265 033 -1 T3 1.265 -1.021IT, -0.7918 10.4919 0 0 I[T2l [148.1871 0.6489396.978 -1.021 IT,J L-0.7918 LO