Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
H0: Type of counselling and the outcome are
independent.
Ha: Type of counselling and the outcome are not
independent.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square test for independence.
Analyze sample data. Applying the chi-square test for independence to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic. Based on the chi-square statistic and the degrees of freedom, we determine the P-value.
1) The sampling method is simple random sampling.
2) The variables under study are each categorical.
3) If sample data are displayed in a contingency table, the expected frequency count for each cell of the table is at least 5.
DF = (r - 1) * (c - 1) = (2 - 1) * (2 - 1)
D.F = 1
Er,c = (nr * nc) / n
Χ2 = 5.38
where DF is the degrees of freedom.
The P-value is the probability that a chi-square statistic having 1 degrees of freedom is more extreme than 5.38.
We use the Chi-Square Distribution Calculator to find P(Χ2 > 5.38) = 0.02
Interpret results. Since the P-value (0.02) is less than the significance level (0.05), we have to reject the null hypothesis. Thus, we conclude that there is a relationship between type of counselling and the outcome.
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