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From the book of Halliday-Fundamentals-of-Physics-Extended-9th page 809. Figure 30-17. ....

1- Demonstrate the total inductance.*

4t ( 2 08642 0 08642 (A) ,A (AM

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Answer #1

We can see The Voltage at 2ms is 6V across resistor and 4V across inductor

The Voltage is given by

V_R = V_{max}[1-\exp (\frac{-Rt}{L})]

V_L = V_{max}\exp (\frac{-Rt}{L})

Putting t=2ms

4 = 10\exp (\frac{-R*2*10^-^3}{L})

\tau = \frac{L}{R} = \frac{-2*10^-^3}{\ln (0.4)} = 2.183 ms

Total inductance is given by

L = R*(2.183*10^-^3) H

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From the book of Halliday-Fundamentals-of-Physics-Extended-9th page 809. Figure 30-17. .... 1- Demonstrate the total inductance.* 4t ( 2 08642 0 08642 (A) ,A (AM 4t ( 2 08642 0 08642 (A) ,A (AM
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