Question

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Write a program that generates an array filled up with random positive integer number ranging from 15 to 20, and display it on the screen. After the creation and displaying of the array, the program displays the following: [Plosition [RJeverse, [Ajverage, [SJearch, [Qjuit Please select an option: Then, if the user selects: -P (lowercase or uppercase): the program displays the array elements position and value pairs for all member elements of the array -R (lowercase or uppercase): the program displays the reversed version of the array -A (lowercase or uppercase): the program calculates and displays the average of the arrav elements -S (lowercase or uppercase ): the program asks the user to insert an integer number and look for it in the array, returning the message wheher the number is found and its position ( including multiple occurences), or is not found. -Q (lowercase or uppercase): the program quits. NOTE: Until the last option ('q' or 'Q) is selected, the main program comes back at the beginning, asking the user to insert a new integer number.

Answer 1

#include <iostream>
#include<cstdlib>
#include <ctime>

using namespace std;


void display( int arr[] ,int size ){
    for (int i = 0; i < size ; ++i) {{


            cout<< arr[i] << " index  " << i;

        }
       cout<< endl ;

    }


}
void reverse( int arr[]  , int size ){

cout<< " THe array element in Reverse order is : " << endl;
    for (int i = size-1 ; i>=0  ; --i) {

        cout<< arr[i]<<" at index "<< size - 1 << endl ;

    }

   cout<<  endl ;

}


double average_array( int arr[]  , int size ){
double sum = 0 ;
    for (int i = 0; i <= size  ; ++i) {

        sum = sum + arr[i];


    }

    return sum/size ;// this will be the average

}

int search( int arr[]  , int size  , int element ){
int count = 0  ;
    for (int i = 0; i <=size  ; ++i) {

        if( arr[i] == element ){
            if ( count  == 0 ){
            cout << element << " is found at index : ";
                count++ ;}

            cout<< i  << " , ";

        }

    }
    cout<<endl ;

    if( count== 0 )
        cout<< " The searched element does not exist in the array "<< endl ;
}

int main(){
int arr[10];
   // to calculatee size of the array
    int size = sizeof(arr)/ sizeof(arr[0]);

    //

    srand(time(0));

    for (int i = 0; i <= size  ; ++i) {
        arr[i] =( rand() %5)  + 15 ;
    }
    char option ;
    int val ;//what to search
    while( option != 'Q' || option != 'q'){
    cout<< " Enter p to display array elements ."<<endl;
cout<<"Enter R to display reverse version of array "<< endl ;
    cout<< "Enter A to display average of the array elements"<< endl ;
    cout<< "Enter S to search an element in array "<< endl ;
    cout << "Enter Q to quit the program ";
    cin>> option;
        if( option == 'Q' || option == 'q')
            exit(1);

       if( option == 'P'|| option == 'p')
           display(arr , size );

    if( option == 'R' || option == 'r')
        reverse(arr , size );
    if( option == 'A' || option == 'a')
        cout<<"The average of all elements in the array is " << average_array(arr , size ) << endl<< endl << endl ;

    if( option == 's' || option == 'S') {
        cout << "Enter the element to search :";
        cin >> val;
        cout << endl;
        search(arr, size, val);


    }

    }

   return 0 ;

}

Enter p to display array elements Enter R to display reverse version of array Enter S to search an element in array Enter A to display average of the array elements Enter q to quit the programp 18 index 19 index 1 18 index2 18 index 3 17 index 8 index5 16 index 6 17 index 7 15 index 17 index 9 Enter p to display array elements Enter R to display reverse version of array Enter A to display average of the array elements Enter S to search an element in array Enter to quit the program THe array element in Reverse order is: 17 at index9 5 at index9 17 at index9 16 at index9 18 at index9 17 at index9 18 at index 9 18 at index9 19 at index9 18 at index9 Enter p to display array elements Enter R to display reverse version of array Enter A to display average of the array elements Enter s to search an element in array Enter to quit the programa The average of all elements in the array is 19.2

Enter p to display array elements Enter R to display reverse version of array Enter A to display average of the array elements Enter S to search an element in array Enter Q to quit the programs Enter the element to search :19 19 19 is found at index 1,10, Enter p to display array elements Enter R to display reverse version of array Enter A to display average of the array elements Enter s to search an element in array Enter Q to quit the programq Process finished with exit code 1