(a) Consider a parallel plate capacitor with static charge density σ and no medium between the disk and the capacitor. Suppose the capacitor is placed in such a way that the xy plane bisects...
The figure shows a parallel plate capacitor. The surface charge density on each plate is 8.8 x 10-8 C/m2. The point P is located 1.0 x 10-5 m away from the positive plate. Which one of the following statements concerning the direction of the electric field between the plates is true? O It points to the left O It points to the right O It points up out of the plane of the page. O It points toward the negative...
The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates. While the battery remains connected, a dielectric slab of thickness b and dielectric constant κ is placed between the plates as shown. Assume A = 130 cm2, d = 1.94 cm, V0 = 72.6 V, b = 0.735 cm, and κ = 3.15. Calculate (a) the capacitance,(b) the charge on the capacitor plates,(c) the electric field in the gap, and(d)...
Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +4.58C. The charge per unit area on each plate has a magnitude of = 3.37 × 10-6 C/m2. The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges?
Two charges are placed between the plates of a parallel plate capacitor. One charge is +q1 and the other is q2 = +4.56C. The charge per unit area on each plate has a magnitude of = 8.63 × 10-3 C/m2. The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges?
Consider an ideal parallel plate capacitor, having vacuum between two plates of area A and separation d. The shape of the plates is arbitrary. By the following steps, prove that the capacitance is 0 d where ε0 is the permittivity. Assume that the charge on each plate is electric field E between the plates is uniform. , and that the Use Gauss' law to calculate the electric field E between the plates in terms of Q and A. (Use a...
Suppose two plates lie in parallel horizontal planes, one plate in the xy plane at z = 0 and the other plate in the plane that is parallel to the xy plane at z = 10 mm. Between the plates is a constant electric field directed vertically upward (that is, in the positive z direction). A proton and an electron are launched in the positive x direction with the same initial velocity from position (0, 0, 5.0 mm). Part A...
Two 2.1-cm-diameter-disks spaced 1.6 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.8×105 V/m . What is the voltage across the capacitor? How much charge is on each disk?An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.5×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.4-cm-diameter-disks spaced 2.0 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.1×105 V/m . A. What is the voltage across the capacitor? B. How much charge is on each disk? (in C) C. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate?
Two 2.4-cm-diameter-disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.9×105 V/m . Part A) *ANSWERED - What is the voltage across the capacitor? - V=740V Part B) How much charge is on each disk? q1,q2= ?C Part C) An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate? vinitial= ??
Two 2.3-cm-diameter-disks spaced 1.9 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0×105 V/m . How much charge is on each disk? b. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.2×107 m/s . What was the electron's speed as it left the negative plate?