Question

The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates.


The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates. While the battery remains connected, a dielectric slab of thickness b and dielectric constant κ is placed between the plates as shown. Assume A = 130 cm2, d = 1.94 cm, V0 = 72.6 V, b = 0.735 cm, and κ = 3.15. Calculate (a) the capacitance,(b) the charge on the capacitor plates,(c) the electric field in the gap, and(d) the electric field in the slab, after the slab is in place.


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