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Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing poin

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No' of moles of HI = [wt of HI] / [Gram.Mol.Wt of HI ] = 4.3 g / 128 g = 0.0362

In Aqueous solutions HI on dissociation gives H+ and I-( total 2 Ions).

so the total number of moles of ions in the HI Aq solution = 2 x 0.0362 moles = 0.0672 moles

No' of moles of glycerin = [wt of glycerin] / [Gram.Mol.Wt of glycerin ] = 4.3 g / 92 g = 0.0467 moles

note: glycerin does not dissociates in water.

No' of moles of CaCl2 = [wt of CaCl2] / [Gram.Mol.Wt of CaCl2] = 4.3 g / 111 g = 0.0387

In Aqueous solutions CaCl2 on dissociation gives Ca2+ and 2 Cl-(total 3 Ions).

so the total number of moles of ions in the CacCl2 Aq solution = 3 x 0.0387 moles = 0.1162 moles

As the number of moles of ions/particles in water increases , the freezing point of solution decreases and the boiling point of solution increases.

Order of freezing point :   water    >     glycerin     >      HI     >    CaCl2

       (Highest FP) (4)               (3)                  (2)          (1) (lowest FP)

Order of Boiling Point : CaCl2     >   HI          > glycerin    >     water

                   (Highest BP) (4)               (3)                  (2)                (1) (lowest BP)

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