No' of moles of HI = [wt of HI] / [Gram.Mol.Wt of HI ] = 4.3 g / 128 g = 0.0362
In Aqueous solutions HI on dissociation gives H+ and I-( total 2 Ions).
so the total number of moles of ions in the HI Aq solution = 2 x 0.0362 moles = 0.0672 moles
No' of moles of glycerin = [wt of glycerin] / [Gram.Mol.Wt of glycerin ] = 4.3 g / 92 g = 0.0467 moles
note: glycerin does not dissociates in water.
No' of moles of CaCl2 = [wt of CaCl2] / [Gram.Mol.Wt of CaCl2] = 4.3 g / 111 g = 0.0387
In Aqueous solutions CaCl2 on dissociation gives Ca2+ and 2 Cl-(total 3 Ions).
so the total number of moles of ions in the CacCl2 Aq solution = 3 x 0.0387 moles = 0.1162 moles
As the number of moles of ions/particles in water increases , the freezing point of solution decreases and the boiling point of solution increases.
Order of freezing point : water > glycerin > HI > CaCl2
(Highest FP) (4) (3) (2) (1) (lowest FP)
Order of Boiling Point : CaCl2 > HI > glycerin > water
(Highest BP) (4) (3) (2) (1) (lowest BP)
Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For...
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