syms y(t)
Dy = diff(y);
ode = diff(y,t,2)-6*diff(y,t)+9*y == t*exp(3*t);
cond1 = y(0) == 0;
cond2 = Dy(0) == 5;
conds = [cond1 cond2];
ySol(t) = dsolve(ode,conds)
ySol(t) = 5*t*exp(3*t) + (t^3*exp(3*t))/6
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syms y(t)
Dy = diff(y);
ode = diff(y,t,2)+16*y == 8*cos(4*t);
cond1 = y(0) == 0;
cond2 = Dy(0) == 0;
conds = [cond1 cond2];
ySol(t) = dsolve(ode,conds)
ySol(t) = cos(12*t)/16 - cos(4*t)/16 + sin(4*t)*(t + sin(8*t)/8)
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syms y(t)
Dy = diff(y);
ode = diff(y,t,2)-4*diff(y,t)+4*y == 6*exp(2*t);
cond1 = y(0) == 0;
cond2 = Dy(0) == 0;
conds = [cond1 cond2];
ySol(t) = dsolve(ode,conds)
ySol(t) = 3*t^2*exp(2*t)
---------------------------------
syms y(t)
Dy = diff(y);
ode = diff(y,t,2)-4*diff(y,t) == -4*t*exp(2*t);
cond1 = y(0) == 0;
cond2 = Dy(0) == 1;
conds = [cond1 cond2];
ySol(t) = dsolve(ode,conds)
ySol(t) = t*exp(2*t)
please solve with mathlab and post screenshots of the code Circle your final answer. 2. y" +16y 8 cos(4t) y(o)-y'(O)- 2.У Circle your final answer. 2. y" +16y 8 cos(4t) y(o)-y'...
please solve with mathlab and post screenshots of the code 10.y" + 2y' +10y -6e sin(3t),y(0) 0,y'(0) 1 10.y" + 2y' +10y -6e sin(3t),y(0) 0,y'(0) 1
cos 4t 1:[0,) 3. Solve for y(t): y” +16y = f(t) = { with y(0) = 0 and y'(0) = 0. 0,if tn. Saleserstos se va posar este mai 90 -m70-e Stepl. Answer: y(t) =
Solve the initial value problem y" + 8y' + 16y = 0, y(-1) = 2, y' (-1) = 5. Equation Editor Common 2 Matrix o @ sin(a) seca) s in-(a) cos(a) csca) cosa tan(a) cota) tana) Va Va la U yt) =
Use MATHLAB to answer the following question. Post your full working code and a screenshot of the output! 1. Write a function sumsteps2 that calculates and returns the sum of 1 to n in steps of 2, where n is an argument passed to the function. For example, if 11 is passed, I will return 1+3+5+ 7 + 9 + 11. Do this using a for loop. Calling the function will look like this: >> sumsteps 2(11) ans = 36...
Please circle your final answer! Question 13 Not yet answered Marked out of 10.00 Solve the following initial value problem. dy/dx + 3xy - 2x e^(-x) = 0 (first order linear DE) y(0) = 1000 Note that a b = ab. Flag question Select one: O a. y = (x2 + 1000)^{-x} O b. y = (x2 - 100)^{-x*} C. y =( X2 - 1000)^{-x*} d. y = (2x2 + 1000)^{-x}
SOLVE #3 AND #4 PLEASE Use the Laplace transformation to solve the IVP. 1. y"-6y' + 9y-24-9t, y(0)-2, y, (0)-0 2. 9y" - 12y'4y50ey(0)--1,y'(0)2 3. У"-2y'--. 1 2 cos(2t) + 4 sin(2t),y(0)-4,y'(0)-0 Use the Laplace transformation to solve the IVP. 1. y"-6y' + 9y-24-9t, y(0)-2, y, (0)-0 2. 9y" - 12y'4y50ey(0)--1,y'(0)2 3. У"-2y'--. 1 2 cos(2t) + 4 sin(2t),y(0)-4,y'(0)-0
Please solve in MATLAB and provide screenshots of the code and a copy of the code. DO PART B ONLY. Chapter 5, Problem 16P 12 Bookmarks Show all steps: OFF Problem Water is flowing in a trapezoidal channel at a rate of Q= 20 m3/s. The critical depth y for such a channel must satisfy the equation 0 = 1-2B - ZA? where g=9.81 m/s2, Ac = the cross-sectional area (m2), and B = the width of the channel at...
You have not submitted your answer. Solve the initial value problem: 16y" + 10y = 0, y(7/6) = -2, y' (/6) = 1. Give your answer as y=... . Use x as the independent variable. Answer: v=
1 VMware Horizon Sketch the region of integration. Vy cos(y) dy dx (1/8 у 2) 2 6 8 2 4 6 O 8 8H 6 2 4 Eva uate the trated Integra, switching the order of integration if necessary COSTS sin 8-1 Type here to search o *
advanced math homework help before final 5. Consider the following initial value problems: x" + 16x = -20e-2 x(0) = 1 2'0) = 0 (a) (4 points) Solve for X(s), the Laplace transform of r(t). (b) (10 points) Solve for e(t) by inverting X(s). (c) (3 points) Let yt) = 2 cos(4t) - 7 sin(4t) (This is one of the pieces to your answer above). Fill in the right-hand sides to the initial value problem that y solves y (0)...