a) The mid point is 2 light years away from Earth's perspective. From my perspective it is
L = 1.6 light years
the speed of probe is 0.8 c. Therefore it will take 1.6/0.8 = 2 years
Answer: 2 years
b) The relative speed as seen by me is given by
Answer: 0.38462 c
c) In Earth's frame the package will take
years
Answer: 5.2 years
d) By law of conservation of linear momentum the other pack is also moving at 0.87c in the other direction.
Therefore relative velocity between them
Answer: 0.9904 c
e) From my viewpoint the package is travelling at speed
In my frame when I reach half the distance Earth is
light years away.
For 1st 1 year the package is moving at 0.8 c therefore when the package breaks it is
1.6-0.8*1 = 0.8 light years away
at 0.966 c the package will take
0.8/0.966 = 0.8283 years
Answer: 0.8283 years
piloting a state-of-the-art spaceship to α Centauri, which is a star about 4 lightyears away as measured from Earth. Your ship cruises at a speed of 0.6c. For this problem, you can assume that Ea...
Practice Problem 27.3 SOLUTION A spaceship flies past earth with a speed of 0.980c (about 2.97 x 10 m/s) relative to earth. A crew member on the spaceship measures its length, obtaining the value 400 m. What is the length measured by observers on earth? SET UP The length of the spaceship in the frame in which it is at rest (400 m) is a proper length in this frame, corresponding to lo in We want to find the length...