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piloting a state-of-the-art spaceship to α Centauri, which is a star about 4 lightyears away as measured from Earth. Your shi
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Answer #1

a) The mid point is 2 light years away from Earth's perspective. From my perspective it is

2V1-0.62-1.6

L = 1.6 light years

the speed of probe is 0.8 c. Therefore it will take 1.6/0.8 = 2 years

Answer: 2 years

b) The relative speed as seen by me is given by

u' = \frac{u-v}{1-\frac{uv}{c^2}}

0.8c _u0.6c

uー-cー0.384620 13

Answer: 0.38462 c

c) In Earth's frame the package will take

= 5.2 13years

Answer: 5.2 years

d) By law of conservation of linear momentum the other pack is also moving at 0.87c in the other direction.

Therefore relative velocity between them

0.87c-(-0.87c)

Answer: 0.9904 c

e) From my viewpoint the package is travelling at speed

0.6c)-0.9660 0.87c(-0.6c)一一0.966C 1

In my frame when I reach half the distance Earth is

2V1-0.62-1.6 light years away.

For 1st 1 year the package is moving at 0.8 c therefore when the package breaks it is

1.6-0.8*1 = 0.8 light years away

at 0.966 c the package will take

0.8/0.966 = 0.8283 years

Answer: 0.8283 years

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piloting a state-of-the-art spaceship to α Centauri, which is a star about 4 lightyears away as measured from Earth. Your ship cruises at a speed of 0.6c. For this problem, you can assume that Ea...
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