Question

Golden ratio method is recommended by the solution and the numerical solution is 4.493335656115932 (or anything accurate up to 2 dp)

(2) Maximum of a function We consider the function, f(x) = ( Sinar Provided that there is a local maximum in the interval r 4

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Answer #1

\small f(x) = \left(\frac{sinx}{x}\right)^{2}

\small f'(x) = x\cos x - \sin x

For maxima f'(x) must be zero.

\small x\cos x - \sin x = 0\; \; \; \; \; \; ;\; \; \; \; \; x\epsilon [4,5]

Let us use the bisection method, (I'm using f(x) instead of f '(x) from here on)

4+5 First guess value,11 =-= 4.5 f(x) 4.5 * cos 4.5-sin 4.5 0.02894902022 > 0 Second guess value,x2= f(x2) 4.25 * cos 4.25-si

4.375+ 4.5 4.4375 Fourth guess value,14 f(4.4375* cos4.4375 -sin4.4375-0.24206004825 0 Fifth guess value,15 = ()0.0217040656

4.484375 +4.5_44021875 17 f(17) 4.4921875+4.5 = 4.49609375 f(28) 78 -一0.0053581 7723 < 0 0.01178060816>0 4.49609375 4.4921875

Proceeding further will guide you to the exact value of the answer. You can also use other numerical techniques.

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By plotting the function f '(x) also one can find the solution

10 10 5 5 0 0 5 10

above is the graphical representation of f '(x)

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