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Borrowing $10 Per Month We continue with the same example: you borrow $10 per month from your friend. On each of these loans,

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Solution: Let Principal be $R, Rate =R% p.a, Time =t years.

(i) When interest is compounded annually:

Amount after t years

= P(1 + 100

(ii) When interest is compounded half-yearly:

Principal = $R, Rate =R% p.a=(R/2)% per half-yearly,Time =t years=(2t) half-years

Amount after t years

R/2 100

(iii) When interest is compounded quarterly:

Principal = $R, Rate =R% p.a=(R/4)% per quarter,Time = t years=(4t) quarters.

Amount after t years

At R/4 100

(iv) When interest is compounded monthly:

Principal = $R, Rate =R% p.a=(R/12)% per month,Time = t years=(12t) months.

Amount after t years

12t 100

In our problem, I borrow $10 per month from my friend. On each of these loans, my friend charges 30% in interest per year, compounded monthly.

For 12th month loan amount = $10.

Number of months of interest =0

Therefore, amount owed on loan at the end of the year =$10(No interest)

For 11th month loan amount = $10.

Number of months of interest =1

Therefore, amount owed on loan at the end of the year

R/12 100

0110) 30/12

-106-ל

=10* 1.025=10.25

For 10th month loan amount = $10.

Number of months of interest =2

Therefore, amount owed on loan at the end of the year

R/12 100

30/12 10 1 + 100

=10\left ( 1+\frac{1}{40} \right )^{2}

=10*1.0506=10.506

For 9th month loan amount = $10.

Number of months of interest =3

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{3}

=10* 1.0768=10.768

For 8th month loan amount = $10.

Number of months of interest =4

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{4}

=10*1.1038=11.038

For 7th month loan amount = $10.

Number of months of interest =5

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{5}

=10*1.1314=11.314

For 6th month loan amount = $10.

Number of months of interest =6

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{6}

=10*1.1596=11.596

For 5th month loan amount = $10.

Number of months of interest =7

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{7}

=10*1.1886\right )=11.886

For 4th month loan amount = $10.

Number of months of interest =8

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{8}

=10*1.2180\right )=12.18

For 3rd month loan amount = $10.

Number of months of interest =9

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{9}

=10*1.2488\right )=12.488

For 2nd month loan amount = $10.

Number of months of interest =10

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{10}

=10*1.2800\right )=12.8

For 1st month loan amount = $10.

Number of months of interest =11

Therefore, amount owed on loan at the end of the year

=10\left ( 1+\frac{1}{40} \right )^{11}

=10*1.3120\right )=13.12

Therefore,

Month Loan amount

Number of

months

of interest

Amount owed

on loan at the end

of the year

12 $10 0 $10
11 $10 1 10.25
10 $10 2 10.50
9 $10 3 10.768
8 $10 4 11.038
7 $10 5 11.314
6 $10 6 11.596
5 $10 7 11.886
4 $10 8 12.18
3 $10 9 12.488
2 $10 10 12.8
1 $10 11 13.12
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