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HELPPPP5 Hydraulic Press ●4 11.0 ft Flow 10.0 ft 2.0 ft 1 6 3.0 ft Filter Pump FlowThe diagram on the next slide shows a fluid power system for a hydraulic press. The following is known: The volume flow rate

5 Hydraulic Press ●4 11.0 ft Flow 10.0 ft 2.0 ft 1 6 3.0 ft Filter Pump Flow
The diagram on the next slide shows a fluid power system for a hydraulic press. The following is known: The volume flow rate is 35 gpm. The hydraulic fluid has a specific gravity of 0.87 and v-4.30X10+ ft'/s. The power input to the pump is 20 hp. . The pump efficiency is 80 percent. The filter has a resistance coefficient K-1.85 based on the velocity head in the suction line. All piping is 2-in schedule 40 steel. The total length of all piping is 55 feet. The valve before the pump is a fully open globe value. The check valve after the first 90° standard elbow is a swing type check valve. Compute the following: The power removed from the fluid by the hydraulic press (report the result in hp) Clearly show all work, any assumptions made and intermediate steps in your derivation. Show the individual energy losses. Report all results in US units (feet, psi, etc.)
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Given Dala Specific savit-8 1 ea input to the pum gesestance Coefficient sts; -Att piptng 2-in schedude uo steel 528 e = 0.8x8800 lb-ft/s 2.9 Pa 29 tlene (aid ha is Ewensy add ition し(1-0) 29 2 in Schedeule uo steel Al% 0 0218 fe CS Scanned w CamScan2 X3 2.2 take Ve S4-28)x (0-078) 2042-4 ft = 2042-4 x(54,26)x(0.078) CS Can8 6y7. 194 Lo ft/s S.73 h Pp canned with amScan

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HELPPPP 5 Hydraulic Press ●4 11.0 ft Flow 10.0 ft 2.0 ft 1 6 3.0 ft Filter Pump Flow The diagram on the next slide shows a fluid power system for a hydraulic press. The following is known: The volume...
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