Question

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4. a. For the molecule below, if simple splitting (follows the N+1 rule) occurs, Ha should appear as a (circle one: singlet, doublet, triplet, quartet) and Hb should appear as a (circle one: singlet, doublet, triplet, quartet) На 0 нь Hc b. Because Hb is attached to a chiral carbon atom, the molecule has diastereotopic Hs and the splitting becomes more complex. The nmr signal for Ha shows up in two places, as shown below. Explain each of these 4 line doublet of doublet patterns (looks like each line of a doublet has been split into a doublet) 3.4 3.2 3.0 2.8 ppm b. The nmr signal for Hb is shown below. Explain this 8 line pattern. 2.3 2.2

Answer 1

Solution : _ Gien-tat Hb Shalb appea, as a guartel doe to 3 Corlbon 1 HC photon the Ha potnw Caple cdhe otooto gtve doublet of ccoblet ta potons to gve 4 peaks Rutbei he Re