(a)
Total demand = 200+10+60+20 = 290 (x1000 pounds)
Total supply = 20+20+200 = 240 (x1000 pounds)
Total demand is greater than supply.
Objective is to satisfy the most demand.
Therefore, this can be formulated as a Maximal network flow model
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(b) The network graph is following:
Number on each arc shows the capacity (maximum flow) along that arc. Objective is to find the maximal flow from source node 1 to destination node 9
Nodes 2,3,4 represent the three silos and nodes 5,6,7,8 represent the four farms.
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(c) Network flow model is following:
Let Xij = flow from node i to node j
Max X12+X13+X14
s.t.
X12-X25-X26-X27-X28=0
X13-X35-X36-X37-X38=0
X14-X45X46-X47-X48=0
X25+X35+X45-X59=0
X26+X36+X46-X69=0
X27+X37+X47-X79=0
X28+X38+X48-X89=0
X12<=20
X13<=20
X14<=200
X25<=30
X26<=5
X27<=0
X28<=40
X35<=0
X36<=0
X37<=5
X38<=90
X45<=100
X46<=40
X47<=30
X48<=40
X59<=200
X69<=10
X79<=60
X89<=20
Xij >= 0
Chicken feed is transported by trucks from three silos to tour farms. Some of the silos cannot ship directly to some farms. The capacities of the other routes are limited by the number of trucks...