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a6-A 105 rot ton co
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Answer #1

Magnetic field at a distance r from a long straight current wire = B = u0I/2\pir

Magnetic field at the center of the loop is Bc= u0I1/2\pi(r+0.05)

= 2×10-7×20/0.2= 4×10-5 T

Inward the plane of loop

(2) force on AD = msgnetic field at AD× current I2 × length AD

= u0I1I2L/(2\pir)= 2×10-7×20×12/(0.15)= 3.20×10-5N leftwards towards strait wire

Force of BC arm = 2×10-7×20×12×0.3/0.25= 1.92×10-5N rightwards.

(3) net force on loop = (3.20-1.92)×10-5N = 1.08×10-5 N leftwards

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