25)
Sample mean of difference = -26.80
26)
Sample std.dev of difference= 81.1402
27)
test statistics:
t = xbar / (sd/sqrt9n))
= -26.80/(81.1402/sqrt(10))
= -1.044
28)
two tailed
Hypothesis are as:
H0 : mud = 0
Ha: mud not =0
29)
df = 10 - 1 = 9
30)
p value = 2 *P(t < -1.044) with df = 9
= 2* 0.1618
P value= 0.3236
As p value > 0.01 Fail to reject H0
31)
t value at 99% = 3.250
CI = xbar +/- t (sd/sqrt(n))
= -26.80 +/ - 3.250 * (81.1402/sqrt(10))
= (-110.1868 , 56.5868 )
The 99% Ci is (-110.1868 , 56.5868 )
Use the following information to answer questions 25-31 A traveler wants to know if the prices of hotels are different. She samples 10 cities and finds the prices below. Use a paired-sample t-t...