Homework Answers
a)
Weld size=3/8=6/16
D=6
Load=150 kips
Let length of weld required be l
1.392*6*l=150
l=17.96~=18 inches
Minimum 18 in weld length is required
b)
Weld length=10 in on each side
Weld size=1/2"=8/16"
D=8
Capacity of weld of one side=1.392*8*10=111.36 in
Applied load =P
Eccentricity=5 in from centroid
This is like a simply supported beam with overhang wherein welds are supports and load is acting at overhang
Shear on weld nearer to the load =P*(5+2)/4=1.75P
1.75P=111.36
P=63.6 kips
Therefore maximum allowable P=63.6 kips
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