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Work out the highlighted questions (3-6) clearly and with units, please. Thanks!
4/5 a the minimum kinetic energy at the apping point? (C) Use conservation of energy to determine the minimum angular velocit
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Answer #1

Patley, M =250kg radius, R = 0.8 = 0.4m. i = 0 - s = 12orad/s. al to Energe given by motor flywheel, = KE of totation Of flyc

E = L (20) (1202) b) E = 144000J Sawblade, m= 80kg 8 = 1 = 0.5m w Let Speedo, be - common angular momentum is Angular conservT = 20 + 180l6o.s . = 30 kg m? L = Ls 2 Iws = Iw = 20% 120 30 w = 80 8ad/s Initial KE Ki= l I wa K. = 1.44X 105 J

Final RE, Kg = 1 I wa Ks = Į (3010801 Ks = 9.64104 T Loss of cnergy, AK = Ki - Ks. AR= 1.444105 - 9.6 4104 = 4.8x10t J. 4. do

X = (3.47 p = (-8,6 Kg m/s 8 = 3it4j m = - 8it Gj Kg m/s Angular momentum T = 3i+j) *(-3i+j) = 0 - 0 + KK 346 - (-8x4)] I a 5

2 = (2,6lm P = (-1,-3) Agnols = (21 +6; ) x ( - 1h 37 = 1 i j 1- -3 0 1 = 0 - 0 +K(-676) It is reapsising to see that angular

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