1) conservation of linear momentum
m1 = 1 kg
m2 = 2 kg
just before the collsion,
the sped of m1, u1 = sqrt(2*g*L)
= sqrt(2*9.8*0.2)
= 1.98 m/s
a) speed of the block just after the collsion,
v2 = 2*m1*u1/(m1+m2)
= 2*1*1.98/(1+2)
= 1.32 m/s
b) velocity of pendulum after the collsion,
v1 = (m1-m2)*u1/(m1+m2)
= (1-2)*1.98/(1+2)
= -0.66 m/s
vertical height raised by the pendulum,
h = v1^2/(2*g)
= 0.66^2/(2*9.8)
= 0.022 m
= 2.2 cm
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