The proportion of adult women in a certain geographical region is approximately 51%. A marketing survey telephones 300 people at random. Complete parts a through e below. b) What is the standard deviation of that proportion?
Solution
Given that,
p = 51%=0.51
1 - p = 1-0.51=0.49
n = 300
standard deviation of that proportion
= [p ( 1 - p ) / n] = [(0.51*0.49) /300 ] =0.029
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