Applied load = 1000 lb
length of joint = 1 in, width of joint = 0.5 in
Area of the bond = length*width = 1*0.5 = 0.5 in2
we have ,
yield = 6675 Psi,
permisible = applied load/area = 1000/0.5 = 2000 lb/in2 = 2000 Psi
therefore FOS = 6675/2000 = 3.3375
Problem 2: The bonded joint below is loaded with 1000 lb as shown. The joint is 0.5in wide and bonded with 0.010" thick bondline of EA9394 epoxy. Calculate the factor of safety against flat-wise...
Problem 1: The bonded joint below is loaded with 1000 lb as shown. The joint is 0.5in wide and bonded with 0.010" thick bondline of EA9394 epoxy. Calculate the factor of safety against shear failure of this bond. EA9394 has lap shear strength of 4200 psi and a tensile strength of 6675 psi. 11in Problem 2: The bonded joint below is loaded with 1000 lb as shown. The joint is 0.5in wide and bonded with 0.010" thick bondline of EA9394...