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l. (why?) Finally, r apur By the number of moles of vapor to obtain the molecular mass. molecular massmoles of vapor Determin
19.) Y ou have obtained the following data from a monohybrid cross (F, x F) between two pink petunias. 10 pts E Generation re
l. (why?) Finally, r apur By the number of moles of vapor to obtain the molecular mass. molecular massmoles of vapor Determine the average molecular mass of the unknown from your three trials. (You may use the best two trials if one is very different from the others.) Questions: 1. If the outside of your flask is not dry when the first mass determination is made and it is dried for the second mass determination, what effect will that have on your results? 2. What will be the effect on your results if all of the liquid is not vaporized while heating? 3. Which assumption would lead to the greatest error in your results, explain why? (a) assume temperature is 250 C, (b) assume the flask volume is exactly 125 mL, (d) assume the barometric pressure is exactlv 760 torr.
19.) Y ou have obtained the following data from a monohybrid cross (F, x F) between two pink petunias. 10 pts E Generation results: 260 white 520 pink 220 red Do a Chi Square analysis of this data set and determine whether it fits a Mendelian model for the cross described above. Write your hypothesis: Use the Chi Square table below to accept or reject the hypothesis that this is Mendelian. How many degrees of freedom are you going to use from the table? Circle the correct critical x value from the table below. Chi-Square Probabilities df 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.005 0.001 0.004 0.016 2.706 3.841 5.024 6.635 7.879 2 0.010 0.020 0.051 0.103 0.211 4.605 5.991 7.378 9.210 10.597 3 0.072 0.115 0.216 0.352 0.584 6.251 7.815 9.348 11.345 12.838 0.207 0.297 0.484 0.711 1.064 7.779 9.488 11.143 13.277 14.860 5 0.412 0.554 0.831 1.145 1.610 9.236 11.070 12.833 15.086 16.750 一 7 0.989 1.239 1.690 2.167 2.833 12.017 14.067 16.013 18.475 20.278 8 1.344 1.646 2.180 2.733 3.490 13.362 15.507 17.535 20.090 21.955 9 1.735 2.088 2.700 3.325 4.168 14.684 16.919 19.023 21.666 23.589 10 2.156 2.558 3.247 3.940 4.865 15.987 18.307 20.483 23.209 25.188 0.676 0.872 1.237 1.635 2.204 10.645 12.592 14.449 16.812 18.548 Show work for partial credit.
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while 26o x1000 = 500 20 400 22 3. 2

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