Question

Find the area of the region enclosed by the curves:

x = -sec^2 y, x = sec^2 y, y = 0, y = pi/4

Using the method of cylindrical shells to find the volume of the solid that results when the region enclosed by the curves is revolved around the y axis.

y = sqrt (x+1), y = 1, x = 1

y = 3 sqrt x, y =0, x =1

Find the volume of the solid that results when the region enclosed by the curves is revolved about the x axis.

y = csc x, y =0, x=pi/3, x = pi/2

Answer 1

2 tau 少2