Question

Jim Mead is a veterinarian who visits a Vermont farm to examine prize bulls. In order to examine a bull, Jim first gives the animal a tranquilizer shot. The effect of the shot is supposed to last an average of 65 minutes, and it usually does. However, Jim sometimes gets chased out of the pasture by a bull that recovers too soon, and other times he becomes worried about prize bulls that take too long to recover. By reading journals, Jim has found that the tranquilizer should have a mean duration time of 65 minutes, with a standard deviation of 15 minutes. A random sample of 11 of Jim's bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 24 minutes. At the 1% level of significance, is Jim justified in the claim that the variance is larger than that stated in his journal? Find a 95% confidence interval for the population standard deviation. (a) What is the level of significance?

(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)

(f) Find the requested confidence interval for the population standard deviation. (Round your answers to two decimal place.)

Answer 1

Solution CiiVVn hat Cm: Tha-effect of tee-Shot %; Sumsed to How lCier, ji does. Soma-ti es et chaks out of &a shsture ll Rat Jim has ound lkat Ra vanqili2er Standard 15 deviat:on tn) Here tla level of 3:qnificanc- actual PoPa lation Standard b Nous ff be

Hore an onder to estkat o test- Stakistic 1 5 1 5 ( 5 2 5-6 ohS And 는 (O c-ve Statistic fer au s 25.6

Poulation Standard deviation be 4-0.0% , h-1 n-1 0%, a X 0.0 2S, 10 Ile- a//er ス0.0 25, loこ 20. 너$13 be. 2.

So, we got a 6139 516 6 5 760 638 '20 ' 너813 512 1387 231, 2321 -51676 2u.173 16-76, 24, ut