Question

64 In the double-slit experiment of Fig. 35-10, the electric fields of the waves arriving at point P are given by E (3.50 pV/m) sin[(1.26 x 1015)t E2 (3.50 V/m) sin[(1.26 X 1015)t 21.5 rad], where time t is in seconds. (a) What is the amplitude of the resultant electric field at point P (b) What is the ratio of the intensity Ip at point P to the intensity Ieen at the center of the inter- ference pattern? (c) Describe where point P is in the interference pattern by giving the maximum or minimum on which it lies, or the maximum and minimum between which it lies. In a phasor diagram of the electric fields, (d) at what rate would the phasors rotate around the origin and (e) what is the angle between the phasors?

Answer 1

a) The amplitude of the resultant electric field is, E=2E, cos 2(3.5x 10-6)cos(212 -1.7x10*V/m 21.5rad ) b)The ratio of the intensity is, 4I cos2 41 cos. 2 2 21.5 = 0.0591 c) The maximum and minimum is, 21.5 2π I. max ar min 3.42 So it is about 3rd maximum and 3"d minimum d)The angular frequency is, o-1.26x10 rad/s e)we take our 3.45, The angle is, 6 (0.45) (360) -162