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QUESTION 13 Q13 (LO2) [2.5 Marks] A 68-kg person gets into an elevator at the lobby level of a hotel together with his 25-kg

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1-Energy consumed= work done by motor =Change in Potential energy =(Mp+Mt)gH=(68+25)x9.81x40=36493 J= 36.5 kJ

2- Power consumed= workdone/time=36.5÷9=4.06 kW

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QUESTION 13 Q13 (LO2) [2.5 Marks] A 68-kg person gets into an elevator at the lobby level of a hotel together with his 25-kg suitcase, and gets out at the 10th floor 40 m above. Answer the following...
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