1-Energy consumed= work done by motor =Change in Potential energy =(Mp+Mt)gH=(68+25)x9.81x40=36493 J= 36.5 kJ
2- Power consumed= workdone/time=36.5÷9=4.06 kW
QUESTION 13 Q13 (LO2) [2.5 Marks] A 68-kg person gets into an elevator at the lobby level of a hotel together with his 25-kg suitcase, and gets out at the 10th floor 40 m above. Answer the following...
QUESTION 13 013 (LO2) [2.5 Marks] A 68-kg person gets into an elevator at the lobby level of a hotel together with his 25-kg suitcase, and gets out at the 10th fl Answer the following questions (by matching the question with correct answer letter) Take g 9.81 m/s2 What is the amount of energy in ki consumed bythe motor A 36.5k of the elevator that is now stored in the suitcase and the B person? [1.5 Marks 9.8 k С...
1. A person gets into an elevator at the lobby level of a hotel together with his 30 kg suitcase, and gets out at the 10th floor, 35 m above. Determine the amount of energy cousum the motor of the elevator that is now stored in the suitcase. (Problem 3-10 from our book.) d by 2. A closed system of mass 2 leg undersoos a progess