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(22) The 99% confidence interval for the TRUE PROPORTION of success for a population is (0.318, 0.462). The random sample siz
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Answer #1

(22)

(i) Sample proportion of success (\hat{p}) is given by:

.4620.39 0.318+0.462

(ii)

Margin of Error (E) is given by:

E 0.462-0.39-0.072

(iii)

Number of successful outcomes (x) is given by:

r = n × p = 300 × 0.39= 117

(23)

(A)

Sample average (\bar{x}) is given by:

8490 7

(B)

Sample Total (\sum x) is given by:

87 × 81-7047

(ii)

Width (W) of confidence interval is given by:

W=90 - 87 = 3

(iii)

W=Z\times SE

For 0.10, Z = 1.645

Substituting:

3-1.645 × SE

So

1.8237 SE 1.645

SE=\frac{\sigma }{\sqrt{n}}=1.8237

Substituting n = 81, we get:

\sigma =1.8237\times 9=16.4134

(24)

n=\frac{Z^{2}_{\alpha /2}\times \sigma ^{2}}{e^{2}}

For \alpha = 0.20, Z = 1.28

\sigma =\sqrt{256}=16

e = 2

Substituting, we get:

n=\frac{1.28^{2}\times 16^{2}}{2^{2}}=105

(25)

(i)

H0: Null Hypothesis: \sigma ^{2} = 127

(ii)

HA: Alternative Hypothesis: \sigma ^{2} < 127

(26)

HA: Alternative Hypothesis: \sigma ^{2} > 127

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(22) The 99% confidence interval for the TRUE PROPORTION of success for a population is (0.318, 0.462). The random sample size is 300. (i) Please determine the SAMPLE proportion of success. (ii)...
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