A fluid moves through a tube of length 1 meter and radius \(r=0.004 \pm 0.0002\) meters under a pressure \(p=3+10^{5} \pm 2000\) pascals, at a rate \(v=0.125 \cdot 10^{-9} \mathrm{~m}^{3}\) per unit time. Estimate the maximum error in the viscosity \(\eta\) if
$$ \eta=\frac{\pi}{8} \frac{p r^{4}}{v} $$
Hint: The error in \(\eta\) is approximated by \(d \eta\), where (by the chain rule) \(d \eta=\frac{\text { iv }}{\text { dr }} d r+\frac{\partial_{p}}{\partial p} d p\).
maximum error \(\approx 15616 \mathrm{pi}\)
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A fluid moves through a tube of length 1 meter and radius r=0.004±0.0002 r=0.004±0.0002 meters under a pressure
A fluid moves through a tube of length 1 meter and radius r=0.008 ± 0.00025 meters under a pressure p=4⋅10^5 ± 1500 pascals, at a rate v=0.875⋅10^−9 m^3 per unit time. Use differentials to estimate the maximum error in the viscosity η given by η=(π/8)(pr^4/v). maximum error ≈