Shavon Clarke 1235) y'' (t) +23y' (t)+120y (t)-o and y(0)#5 and y' (0)-0. The first step in solving this DEQ using the Laplace Transform procedure is to take the Laplace Transform...
Consider the initial value problem y′+3y=10e^(7t) y(0)=4. a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). b. Solve your equation for Y(s). Y(s)=L[y(t)]= c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t)....
1 point) Consider the initial value problem y" + 36y-cos(61), y(0)-6 (0)-8, a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). help (formulas) b. Solv e your equation for Y (s) Y(s) = L { y(t)) = c. Take the inverse...
QUESTION 1 The Laplace Transform y"-16y=16u(t) Use the Laplace Transform to solve y(O)=0 (y'(0)=0.
(1 point) Consider the initial value problem where g)-t ifosi«5 a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). help (formulas) b. Solve your equation for Y(s) (s) = L {y(t)) = c. Take the inverse Laplace transform of both sides...
Q- Solve the problem by Laplace transform, y + 3y = 6, given that at t=0, y=1, then take inverse Laplace transform to get y(t).
(1 point) Use the Laplace transform to solve the following initial value problem: y" +12y' 85y (- 6 (0) 0, y(0)0 Use step(t-C) for ue(t). y(t) = (1/49jeAqt-6))sin(7)step(t-6) (1 point) Use the Laplace transform to solve the following initial value problem: y" +12y' 85y (- 6 (0) 0, y(0)0 Use step(t-C) for ue(t). y(t) = (1/49jeAqt-6))sin(7)step(t-6)
5. Express f(t) using the unit step function an then use the Laplace Transform to solve the given IVP: y' + y = f(t), y(0) = 0, where f(t) = So, ost<1 15, t21
So 0<t<5 Using the Laplace transform, solve the initial value problem y' + y = 3 t5 y'(0) = 0. 9
Take the Laplace transform of the following initial value problem and solve for Y(s)=L{y(t)}: y′′−5y′−24y=S(t) y(0)=0,y′(0)=0 Where S(t)={1, ,0≤t<1 0, 1≤t<2} S(t+2)=S(t) Y(s) = ?
(1 point) Take the Laplace transform of the following initial value problem and solve for Y(8) = L{y(t)}; ſ1, 0<t<1 y" – 6y' - 27y= { O, 1<t y(0) = 0, y'(0) = 0 Y(8) = (1-e^(-s)(s(s^2-6s-27)) Now find the inverse transform: y(t) = (Notation: write uſt-c) for the Heaviside step function uct) with step at t = c.) Note: 1 | 1 s(8 – 9)(8 + 3) 36 6 10 + s $+37108 8-9