Question

Wind Mountain is an archaeological study area located in southwestern New Mexico. Potsherds are broken pieces of prehistoric Native American clay vessels. One type of painted ceramic vessel is called Mimbres classic black-on-white. At three different sites the number of such sherds was counted in local dwelling excavations.

Sitel SiteⅡ Site 62 26 30 22 61 19 41 40 43 51 19 54 60 30 64 54

Shall we reject or not reject the claim that there is no difference in population mean Mimbres classic black-on-white sherd counts for the three sites? Test given α 0,01

Given that P-Value > 0.1, will you reject or fail to reject the null hypothesis?

The P-Value is less than the level of significance and so we fail to reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that not all of the means are equal.

The P-Value is greater than the level of significance and so we fail to reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that all of the means are equal.

The P-Value is greater than the level of significance and so we reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that all of the means are equal.

The P-Value is less than the level of significance and so we reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that not all of the means are equal.

The P-Value is greater than the level of significance and so we reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that not all of the means are equal.

Sitel SiteⅡ Site 62 26 30 22 61 19 41 40 43 51 19 54 60 30 64 54
α 0,01
0 0
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Answer #1

The following table is obtained:

Group 1 Group 2 Group 3
62 26 30
22 61 19
41 40 43
51 19 54
16 60
30 64
54
Sum = 276 146 270
Average = 39.429 36.5 45
Xij2= 12682 6358 13722
St. Dev. = 17.319 18.52 17.731
SS = 1799.7142857143 1029 1572
n = 7 4 6

The total sample size is N = 17

Source of variation sum of square degree of freedom mean sum of square
Between 192.815 2 96.408
Error 4400.714 14 314.337
Total 16

F = (96.408)/(314.337)

F = 0.307

P-value = 0.7407

conclusion :-

  The P-Value is greater than the level of significance and so we fail to reject the null hypothesis that all three means are equal. At 0.01 level of significance, we conclude that all of the means are equal.

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