Question

Sume select the sppropriate test for the following study: Compare ablet computer afher vigwins a new ad campaign. The pat meloded a young female spokesperson, an older female older male spokesperson -12. ANOVA s ANOVA s ANOVA ーfr a new .tonbile. With a-.05 and a sample of.noevalu statistic of z-481. What is the appropriate statistical decisicn the a. R_thesulhypothesis with α-.05 butnot witha- on for this h.spetthe null hypothesis with either α = .05 ora-0101, c. Faltoreject the null hypothesis with either α = .05 or α d There is mot emough information to determine the appropriate 13 A rescarcher is conducting a chi-square test for soodness of fit te eng- 14. Paty wants to test the relationship between income and eamed per year and smoking is measured as number of cigtte should Patty use to test her research question? a Pearson r is measured as number of eigarettes smoked per nce i day, which c. paired-t test d. Spearman r A dentist wanted to examine if milk consumption as a child had an ima 50. He classified his patients as having consumed a lot of milk as a child conhe edo 15. for dentures by vs. no) and as to wi wore dentures by age 50 (es vs. no) What statistical test should he usetoem tr a Pearson r b. Two-way independent-measures ANOVA c Chi-square goodness of fit test d. Chi-square test of independence 16. If Ashley wants to test for GPA differences among first, second-, third-, and fourth-vet you should advise her to use which of the following difference tests? a repeated-measures one-way ANOVA b. independent-measures, one-way ANOVA e. repeated-measures two-way ANOVA d. independent-measures, two-way ANOVA 17 Suppose the correlation between height and weight for adults is +0.40. What proportion (or percent of t variability in weight can be explained by the relationship with height? 40% b.. 60% 16% d. 84% c.
all 6?

Answer 1

12. one-way repeated-measures ANOVA because comparing before and after effect. involves paired measures as 13. Here the degrees of freedom are 30 1 29 The critical value can be calculated in Excel as: CHISQ.INV.RT(O.05,29) 42.55697 Since the critical value is large, do not reject the null hypothesis c Fail to reject the mull bypothesis either 00ora-0.01 14. c. paired t test because sampled units are same. 15. d. Chi-square test of independence because we want to test whether consumption of milk is independent of dentures need or not. 16. b. independent-measures, one-way ANOVA because there are independent groups 17. This proportion is the square of the correlation therefore, 20.402 -0.16 Hence the correct option is c. 1690