Question

this is how output should look

CSC1101 TakeHome Lab02 (1),docx - Compatibility Mode Saved to this PC S Review View. Help Search 3. [11] You have been hired by Projectile Objects to create a calculator for various equations from kinematics. Suppose someone shoots an object and it does projectile motion with an angle of 30, 45 and 60 degrees to the horizontal. Choose it's initial velocity (ex. 10 m/s) find the maximum height it can reach, horizontal displacement and total time required for this motion. Here are the four equations you will be using: V=Vo + at 2, Your program should include the following steps: a. Calculate real valued vertical and horizontal velocity from initial velocity (hint: xvelocity-initialVelocity*cos(angle); yVelocity = initialVelocity*sin(angle), make sure you convert angle from degree to radians like so angle angle pi/180); b. In vertical, do the following: i. Calculate the real value for time (hint: V = Vo + a*t → 0 = yVelocity -gravity time - time- yVelocity/gravity, but since this is the time for half of the vertical motion, the real total time is time 2"time) ii. Calculate the real value for maximum height (hint: maxHeight 5*gravity"(5 time), here we have to halve time because we are only considering the vertical displacement, not total distance traveled) c. In horizontal, do the following: i. Calculate the horizontal displacement (hint: X-Xo + Vo*t → maxLength -0+xVelocity time Use constant value for GRAVITY-9.8 m/s/s, PI 3.1415 and for degree symbol char DEG char(167) (if you are using xcode, you can copy a paste your degree symbol into place of char( 167)). Output your results like so: Welcome to Projectile 0bjects! The object is launched at an initial velocity of: 10 m/s The angle is: 300 Time that the object is in air: 1.02038 t Maximum height reached: 1.27544 m Horizontal displacement: 8.83684 m Welcome to Projectile Objects! The object is launched at an initial velocity of: 10 m/s The angle is: 45° Time that the object is in air: 1.44304 t Maximum height reached: 2.5509 Horizontal displacement: 10.2041 m Welcome to Projectile Objects! The object is launched at an initial velocity of: 10 m/s The angle is: 60 Time that the object is in air: 1.76737 t Maximum height reached: 3.82639 m Horizontal displacement: 8.83731 m your prograni code here If possible, format your oode 1ike this Font "Courier New" Font aize "9" Bold

Answer 1

import java.util.Scanner;
import java.lang.Math;

public class Projectile {
   public static void main(String[] args) {
       int initial_velocity;
       int angle;
       double xvelocity;
       double yvelocity;
       double time;
       double displacement;
       double height;
       double angle_radian;
       Scanner sc = new Scanner(System.in);
       while(true) {
           System.out.println("Welcome to Projectile Objects!");
           System.out.println("===========================\n");
           System.out.println("The object is launched at an initial velocity of:");
           initial_velocity = sc.nextInt();
           System.out.println("The angle is:");
           angle = sc.nextInt();
          
           angle_radian = angle*(3.1415/180);
           xvelocity = initial_velocity*java.lang.Math.cos(angle_radian);
           yvelocity = initial_velocity*java.lang.Math.sin(angle_radian);
          
           time = yvelocity/9.8;
           time = time*2;
          
           height = 0.5*9.18*java.lang.Math.pow((0.5*time), 2);
          
           displacement = xvelocity*time;
          
           System.out.println("Time that the object is in air: "+time+" t");
           System.out.println("Maximum height reached: "+height+" m");
           System.out.println("Horizontal Displacement: "+displacement+" m");
       }
   }
}