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upport Vector Machines 1. Show mathematically that weight vector is orthogonal to the decision boundary. 2. Show that the dis
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Answer #1

Let the decision boundary be defined as w^Tx+b=0. Consider the points x_a and ть, which lie on the decision boundary. This gives us two equations:

w^Tx_a+b=0

w^Tx_b+b=0

Subtracting these two equations gives us w^T\cdot(x_a - x_b)=0 .

Note that the vector x_a - x_b lies on the decision boundary, and it is directed from ть to x_a. Since the dot product w^T\cdot(x_a - x_b) is zero, w^T must be orthogonal to x_a - x_b, and in turn, to the decision boundary.

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upport Vector Machines 1. Show mathematically that weight vector is orthogonal to the decision boundary. 2. Show that the distance from a point vector x on to a decision boundary line y(x)- +bish...
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