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It has been shown n that the discrete Pourier transform(DFT) of a time-varying process discrete h(tk) for (k0,1,2,.. ,N - 1).
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Answer #1

Solution: Let the discrete Fourier transform (DFT) of a time-varying process

h(tk ) : (k = 0.1.2: . . . . Л_1) is given by

H_{n}=\sum_{k=0}^{N-1}h_{k}e^{i2\pi nk/N}~~~~~~~~(i)

If N=8 then (i) becomes, H_{n}=\sum_{k=0}^{7}h_{k}e^{i2\pi nk/8}~~~~~~~~(ii)

(a) Let

N-1 i2Tnk/N

Then the inverse DFT is given by

h_{k}=\frac{1}{N}\sum_{k=0}^{N-1}H_{n}e^{-i2\pi nk/N}

N-1

If N=8, then

H_{n}=\sum_{k=0}^{7}h_{k}e^{i2\pi nk/8} and

h_{k}=\frac{1}{8}\sum_{k=0}^{7}\left [\sum_{k=0}^{7}h_{k}e^{i2\pi nk/8} \right ]e^{-i2\pi nk/8}

(b) Let W=e^{i2\pi/N}. For N=8, W=e^{i2\pi/8}

Then

に0

and

h_{k}=\frac{1}{8}\sum_{k=0}^{7}\left [\sum_{k=0}^{7}h_{k}e^{i2\pi nk/8} \right ]e^{-i2\pi nk/8}= \frac{1}{8}\sum_{k=0}^{7}\left [\sum_{k=0}^{7}h_{k}W^{nk} \right ]W^{-nk}

(c) DFT in matrix form:

Introducing Nx1 vectors

h(to h(t1) UN-1 and H=\begin{bmatrix} H_{0}\\ H_{1}\\ \vdots \\ H_{N-1}\\ \end{bmatrix}

and the NxN matrix,

N-1 2(N-1)

If N=8, then we have

h(to h(ti) h(t7), H=\begin{bmatrix} H_{0}\\ H_{1}\\ \vdots \\ H_{7}\\ \end{bmatrix}

W=\begin{bmatrix} W^{0}& W^{0}& W^{0}&\cdots &W^{0} \\ W^{0}&W^{1} & W^{2} & \cdots &W^{7} \\ W^{0}& W^{2}& W^{4}& \cdots &W^{14} \\ \cdots &\cdots & \cdots & \cdots &\cdots \\ W^{0}& W^{7} &W^{14} & \cdots & W^{49} \end{bmatrix}

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It has been shown n that the discrete Pourier transform(DFT) of a time-varying process discrete h(tk) for (k0,1,2,.. ,N - 1). is given by carry out the Cooley-Tukey formulation of FFT by followin...
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