Question

Objective This activity has the purpose of helping students apply Markov Chain for transtions probabilities and to calculate expected values from a Markov Chain Process. (Objectives 2 & 3) Families who has pet are classified has having one, two or three pets Let say that in a given year, 15% of families with one pet move to a have 3 pets, and 5% move to have 2 pets, also 6% of all families with 3 pets move to having only one pet, and 4% move to a having 2 pets, finally, 4% of all families having 2 pets move to an having 1 pet and 6% move to a 3 pets a) If a family now have one pet. What is the probability that it will have one pet, two pets or 3 pets two years from now? According to Bird lovers, the probability that both bird at stage 1 is 080, what would be the probablity to see only Dabbling in stage 2? Whistler Dabbling Both Neither 0.70 0.20 005 0.05 0.20 0.60 0.10 0.10 0.10 0.10 0.80 0.00 005 005 0.10 0 80 Whistler Both Neither

Answer 1

SoluHon: We have markoue chan usiHh SPaae L, 2 SIHO babi N3 0.05 O 15 0 have one pet ami om Noa is ears 2 6 002 t 009 ii) Probabil,ty that it will have 2 et ears

05)(09)+ 15 0 0.006 二匕0.032 ears rom how e2 005) 0 06 o 135 6 003 heprobab liy will bove ท้า et 2

probabrlity tosee only Dabsling in state 2iS חו ơ.og Ans..
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