please answer using R software and include the statement of the R command to do the test of hypothesis and the R output.
thank you!
Null and alternative hypotheses are
Ho : Mean tensile strength does not vary with machines
Ha : Mean tensile strength varies with machines
R-code
#Read Data
X<- structure(list(m1 = c(17.5,16.9,15.8,18.6,16.4,19.2,17.7,15.4,20.3,15.7,17.8,18.9,14.6,16.7,20.8,18.9,17.5,19.2,16.5,20.5,18.3,16.2,17.5,20.1), names = c("machine1","machine1","machine1","machine1", "machine2", "machine2", "machine2", "machine2", "machine3", "machine3", "machine3", "machine3","machine4","machine4","machine4","machine4","machine5","machine5","machine5","machine5","machine6","machine6","machine6","machine6"), names=1:24), .Names = c("strength","machine"), class = "data.frame", row.names = c(NA, -23L))
dat <- X
#head(dat)
res.aov <- aov(strength ~ machine, data = dat)
anova(lm(strength ~ machine, data =dat))
Output
Analysis of Variance Table Response: strength Df Sum Sq Mean Sq F value Pr(>F) machine 5 5.338 1.0677 0.3068 0.9024 Residuals 18 62.640 3.4800
Given, level of significance = 0.05
Since, p-value = 0.9024
0.9024 > 0.05
that is p-value > level of significance
we do not reject Ho.
Conclusion :
Mean tensile strength does not differ for the six machines
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