Below is the code assembly x86.
BEGIN : mov edx, 0 //load edx with value 0
WHILE : cmp eax, ebx //compare the content of eax and ebx
jl END // Jump to label END if eax < ebx
sub eax, ebx // subtract ebx from eax
inc edx //increment the content of edx by 1 to store the quotient
jmp LOOP //Jump to label WHILE for further iteration
END : Ret //Return
Please comment for any clarification.
8. The following algorithm can be used to carry out division of two non- negative numbers by repeated subtraction. initialize quotient to o WHILE dividend >- divisor DO increment quotient subtr...
This C++ Program consists of: operator overloading, as well as experience with managing dynamic memory allocation inside a class. Task One common limitation of programming languages is that the built-in types are limited to smaller finite ranges of storage. For instance, the built-in int type in C++ is 4 bytes in most systems today, allowing for about 4 billion different numbers. The regular int splits this range between positive and negative numbers, but even an unsigned int (assuming 4 bytes)...