1) P(A) = P(A1) + P(A2) + P(A3) = 1/12 + 1/12 + 1/12 = 3/12 = 1/4
2) P(1 | A) = P(A1) / P(A) = (1/12) / (1/4) = 1/3
3) P(2 | A) = 1/3
4) P(B) = 1 - [P(A) + P(C)] = 1 - [P(A) + P(C1) + P(C2)] = 1 - (1/4 + 1/6 + 1/12) = 1/2
5) P(1 | B) = P(B1) / P(B) = (1/6) / (1/2) = 1/3
6) P(3 | B) = P(B3) / P(B) = (1/4) / (1/2) = 1/2
7) P(B2) = P(2 | B)*P(B) = (1/6)*(1/2) = 1/12
8) P(C) = P(C1) + P(C2) = 1/6 + 1/12 = 1/4
9) P(1 | C) = P(C1) / P(C) = (1/6) / (1/4) = 2/3
10) P(2 | C) = P(C2) / P(C) = (1/12) / (1/4) = 1/3
(1 point) Rework problem 18 from section 3.3 of your text, involving filling in missing probabilities on a tree diagram. Construct a copy of figure 3.11 in your text, where the first outcome is one o...
Rework problem 21 from section 3.3 of your text, involving the selection of colored balls from two bags. Assume that each bag contains 5 balls. Bag a contains 3 red and 2 white, while bag b contains 2 red, 2 white, and 1 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color. (1) What...
(1 point) Rework problem 22 from section 2.4 of your text, involving the assignment of tasks to student union board members. Assume that there are 16 board members: 12 females, and 4 males including Carl. There are 3 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment. (1) Find the probability that both males and females are given a task. (2) Find the probability that Carl and at least one female are given...
(1 point) Rework problem 22 from section 2.4 of your text, involving the assignment of tasks to student union board members. Assume that there are 16 board members: 12 females, and 4 males including Carl. There are 3 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment. (1) Find the probability that both males and females are given a task. (2) Find the probability that Carl and at least one female are given...