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1 point) Find the arclength of the curve r(t)=(2t2,2y2t,int), for 1-t-6. 1 point) Find the arclength of the curve r(t)=(2t2,2y2t,int), for 1-t-6.
(1 point) Find the arclength s(t) of the curve r(t) Don't forget to submit your answer as a function of t. 9t21+ 8t3j + 4t4k from r(0) to r(t). You can assume that t is positive. s(t) (1 point) Find the arclength s(t) of the curve r(t) Don't forget to submit your answer as a function of t. 9t21+ 8t3j + 4t4k from r(0) to r(t). You can assume that t is positive. s(t)
(1 point) Starting from the point (1,1, -3) reparametrize the curve r(t) = (1 – 1t) i + (1 – 1t)j + (-3 – 3t) k in terms of arclength. r(t(s)) = it j+ k
The arclength of the curve r(t) = (2 cos(at/2), 2 sin"(at/2),1), between the points r = (2,0,1) and r = (0,2,1), is given by the expression -] . a37 sin(a4nt/2) cos(azat/2) dt = 06. 02 Fill in the blank for ai, i = 1,...,6. Answers should be integers, no spaces, no punctu- ation, the only non-numeric symbol allowed is a minus sign. where a1, 22, 23, 24, 25 and 26 are integers given by: 01 = A2 = A3 =...
(1 point) Starting from the point (4,3,2)(4,3,2) reparametrize the curve r(t)=(4+3t)i+(3−3t)j+(2−2t)kr(t)=(4+3t)i+(3−3t)j+(2−2t)k in terms of arclength.
(1 point) Starting from the point (-4,-1,0) reparametrize the curve r(t) = (-4+ 3t)i + (-1+2t)j + (0+2t)k in terms of arclength. r(t(s)) it j+ k
(1 point) Consider the path r(t) (16t, 812, 8 Int) defined for t> 0. Find the length of the curve between the points (16, 8, 0) and (48, 72, 8 In(3)).
How do you solve the following? Consider the curve r=(e^(-5t)cos(-t),e^(-5t)sin(-t),e^(-5t). Compute the arclength function s(t): (with initial point t=0).
(1 point) Find a vector equation for the tangent line to the curve r(t) = (2/) 7+ (31-8)+ (21) k at t = 9. !!! with -o0 <1 < 0
(1 point) For the curve given by r(t) = (2t, 5t, 1 – 5t), Find the derivative r'(t) =( > Find the second derivative p"(t) = ( 1 Find the curvature at t = 1 K(1) =
X) 13.4.21 Find an equation for the circle of curvature of the curve r(t)-21 + sin(t) j at the point (z,1). (The curve parameterizes the graph of y = sin | 2x | in the xy-plane.) An equation for the circle of curvature is (Type an equation. Type an exact answer, using π as needed.) X) 13.4.21 Find an equation for the circle of curvature of the curve r(t)-21 + sin(t) j at the point (z,1). (The curve parameterizes the...