(1 point) Starting from the point (1,1, -3) reparametrize the curve r(t) = (1 – 1t)...
(1 point) Starting from the point (-4,-1,0) reparametrize the curve r(t) = (-4+ 3t)i + (-1+2t)j + (0+2t)k in terms of arclength. r(t(s)) it j+ k
(1 point) Starting from the point (4,3,2)(4,3,2) reparametrize the curve r(t)=(4+3t)i+(3−3t)j+(2−2t)kr(t)=(4+3t)i+(3−3t)j+(2−2t)k in terms of arclength.
Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 2t i + (2 − 3t) j + (8 + 4t) k r(t(s)) =
1 point) Find the arclength of the curve r(t)=(2t2,2y2t,int), for 1-t-6.
1 point) Find the arclength of the curve r(t)=(2t2,2y2t,int), for 1-t-6.
(1 point) Find the arclength s(t) of the curve r(t) Don't forget to submit your answer as a function of t. 9t21+ 8t3j + 4t4k from r(0) to r(t). You can assume that t is positive. s(t)
(1 point) Find the arclength s(t) of the curve r(t) Don't forget to submit your answer as a function of t. 9t21+ 8t3j + 4t4k from r(0) to r(t). You can assume that t is positive. s(t)
U © © and Me if it) = (x+4?) 7+ (2+t')}+*k , evaluate S'iltydt Reparametrize the curve with respect to arc length measured from the point where too in the direchin of increasing t. Fit) = (2+3t) i + (8+9+) 3 - 6t he 22 fenchon
reparametrize the curve r(t)= <t,3cost,3sint> with respect to arc lenght
e.) What is the equation of the tangent plane to the function z = x2 + 4y2 at the point with x = 2, y = -1? [8 points) f.) For the curve through space F(t) =< sin(3t), cos(3t), 2t>, what is the unit tangent vector at t = 7/2? [8 points] g.) Starting from t= 0, reparameterize the curve r(t) = (1 - 2t) î +(-4+ 2t)ſ+(-3 – t)k in terms of arclength. [8 points]
(1 point)
Given
R(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tkR(t)=e4tcos(3t)i+e4tsin(3t)j+3e4tk
Find the derivative R′(t)R′(t) and norm of the derivative.
R′(t)=R′(t)= ∥R′(t)∥=‖R′(t)‖=
Then find the unit tangent vector T(t)T(t) and the principal
unit normal vector N(t)N(t)
T(t)=T(t)= N(t)=N(t)=
(1 point) Given R(t) = cos(36) i + e sin(3t) 3 + 3e"k Find the derivative R') and norm of the derivative. R'(t) = R' (t) Then find the unit tangent vector T(t) and the principal unit normal vector N() T(0) N() Note: Yn can can on the hom
plz
show all steps in a readable handwritting for problem number 5,6
& 7
5) Find T(t),n(t), B(t),r(t),k(t) and ρ(t) for r(t)=tT+(3t-1) 6) Find the graph of the osculating circle to the curve y = x2 at the point (1,1) 7) Let r(t) = t21-7j+ 2t2k.Given thata= a:T+aM a) Find the tangential component of the acceleration. b) Find the normal component of the acceleration directly (via the formula for an) and indirectly (using |ã | and ar). Show that they...